phyon解一元二次方程

3L.

ax^2+bx+c=0
求x1,x2,无解
（有过程和结果就行）

李恒道

import math

def calcEquation(a, b, c):
    discriminant = b**2 - 4*a*c
    if discriminant > 0:
        root1 = (-b + math.sqrt(discriminant)) / (2*a)
        root2 = (-b - math.sqrt(discriminant)) / (2*a)
        return root1, root2
    elif discriminant == 0:
        root = -b / (2*a)
        return root
    else:
        return None
a = 1
b = -10
c = 24
roots = calcEquation(a, b, c)
print(roots)