最近没有产出，分享一个面试题，希望gg们各显神通

wwwwwllllk

本帖最后由 wwwwwllllk 于 2023-9-11 23:20 编辑

const dataSource = [
  {value: "1", groupId: 'a'},
  {value: "15", groupId: 'b'},
  {value: "7", groupId: 'a'},
  {value: "9", groupId: 'c'},
  {value: "5", groupId: 'b'},
  {value: "11"}
];

把上面的dataSource数组输出为

[
  [ { value: '1', groupId: 'a' }, { value: '7', groupId: 'a' } ],
  [ { value: '5', groupId: 'b' }, { value: '15', groupId: 'b' } ],
  [ { value: '9', groupId: 'c' } ],
  [ { value: '11' } ]
]

gg们可以给自己限时10分钟，然后不要借助任何工具就自己手写

JKstring

const dataSource = [
    { value: "1", groupId: 'a' },
    { value: "15", groupId: 'b' },
    { value: "7", groupId: 'a' },
    { value: "9", groupId: 'c' },
    { value: "5", groupId: 'b' },
    { value: "11" }
];

const formattedData = dataSource.sort((a, b) => {
    if (a.groupId < b.groupId) {
        return -1;
    } else if (a.groupId > b.groupId) {
        return 1;
    } else {
        return a.value - b.value;
    }
}).reduce((acc, item) => {
    const group = acc.find(group => group[0].groupId === item.groupId);

    if (group) {
        group.push(item);
    } else {
        acc.push([item]);
    }

    return acc;
}, []);

console.log(formattedData);

steven026

1. const dataSource = [
   
2.   {value: "1", groupId: 'a'},
   
3.   {value: "15", groupId: 'b'},
   
4.   {value: "7", groupId: 'a'},
   
5.   {value: "9", groupId: 'c'},
   
6.   {value: "5", groupId: 'b'},
   
7.   {value: "11"}
   
8. ];
   
9. const temp=dataSource.reduce((obj,data)=>{
   
10.     const {groupId}=data
    
11.     obj[groupId]=obj[groupId]||[]
    
12.     obj[groupId].push(data)
    
13.     return obj
    
14. },{})
    
15. Object.values(temp)
    

复制代码

wwwwwllllk

steven026 发表于 2023-9-12 00:48

每个value也要从小到大排列

steven026

wwwwwllllk 发表于 2023-9-12 08:33
每个value也要从小到大排列

1. Object.values(temp).map(i=>i.sort((a,b)=>a.value-b.value))
   

复制代码

王一之

gpt-4来咯

const dataSource = [
  {value: "1", groupId: 'a'},
  {value: "15", groupId: 'b'},
  {value: "7", groupId: 'a'},
  {value: "9", groupId: 'c'},
  {value: "5", groupId: 'b'},
  {value: "11"}
];

let result = dataSource.reduce((acc, cur) => {
  let targetIndex = acc.findIndex(arr => arr[0].groupId === cur.groupId);

  if (targetIndex !== -1) {
    acc[targetIndex].push(cur);
  } else {
    acc.push([cur]);
  }

  return acc;
}, []);

console.log(result);

王一之

脚本猫ide写的

    const dataSource = [
        { value: "1", groupId: 'a' },
        { value: "15", groupId: 'b' },
        { value: "7", groupId: 'a' },
        { value: "9", groupId: 'c' },
        { value: "5", groupId: 'b' },
        { value: "11" }
    ];

    let result = [];

    let empty = [];

    for (let i = 0; i < dataSource.length; i++) {
        let val = dataSource[i];
        if (!val.groupId) {
            empty.push(val);
            continue;
        }
        let index = val.groupId.charCodeAt(0) - 97;
        if (!result[index]) {
            result[index] = [];
        }
        result[index].push(val);
    }
    result.push(empty);
    for (let i = 0; i < result.length; i++) {
        console.log(result[i]);
        result[i] = result[i].sort((a, b) => a.value - b.value);
    }

    console.log(result);

Yiero

本帖最后由 Yiero 于 2023-9-12 13:40 编辑

const dataSource = [
    { value: "1", groupId: 'a' },
    { value: "15", groupId: 'b' },
    { value: "7", groupId: 'a' },
    { value: "9", groupId: 'c' },
    { value: "5", groupId: 'b' },
    { value: "11" }
];

dataSource.sort( ( a, b ) => a.value - b.value );
const dataMap = new Map();
dataSource.forEach( ( data ) => {
    const groupArray = dataMap.get( data.groupId ) || dataMap.set( data.groupId, [] ).get( data.groupId );
    groupArray.push( data );
} )
const result = Array.from( dataMap.values() );
console.log( result );

Yiero

这几天刚学的新东西, 实验性内容(

const dataSource = [
    { value: "1", groupId: 'a' },
    { value: "15", groupId: 'b' },
    { value: "7", groupId: 'a' },
    { value: "9", groupId: 'c' },
    { value: "5", groupId: 'b' },
    { value: "11" }
];

const result = Object.values( 
    Object.groupBy( 
        dataSource.toSorted( ( a, b ) => a.value - b.value ), 
        ( item ) => item.groupId 
    ) 
);

console.log( result );